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Message Posted: Wed, 03 Apr 2013 @ 22:44:54 GMT
<-- Anonymously Posted: Wednesday, April 03, 2013 16:34 -->
No. The HASHROW function is non-invertible - you can't determine the original argument from the result value.
Also, because the range of HASHROW is finite, there may be "collisions". HASHROW(x) = HASHROW(y) does not guarantee x=y.
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