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Message Posted: Fri, 25 Apr 2008 @ 10:02:29 GMT

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I think udf will be best solution. But if you are going with recursive option, try this. [i am using Michael's table/column names]

     with recursive num_found (num,vartext, lvl) as
     (
     select  ''(varchar(2000))  as num, vartext, 1 as lvl  from vartable
     union all
     select num||case when substr(vartext,lvl,1) between '0' and
     '9'  then substr(vartext,lvl,1) else '' end
            , vartext
            , lvl+1
     from num_found
     where lvl <= character_length(vartext)
     )
     select *
     from num_found
     qualify row_number() over (partition by vartext order by lvl
     desc) = 1;

thanks,

Jinesh P V

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