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Archives of the TeradataForumMessage Posted: Sat, 26 Jan 2008 @ 20:25:41 GMT
Dieter Noeth wrote:
No, not the order by in the select, it's the resultset within the Frontend Tool > replace view "test without order by" as > select calendar_date from sys_calendar.calendar > where calendar_date between current_date - 10 > and current_date qualify row_number() > over (order by calendar_date) > 0; > select * from "test without order by"; Actually this works almost perfect. Check this out: If I am running the Select as the following select "THE_WEEK_V" ."WeekID" , "THE_WEEK_V"."WeekCD" , "THE_WEEK_V"."WeekDesc" from RD_VIEWS.THE_WEEK_V The resultset is exactly as I need it. The Result is ordered by the WeekID Week Week Id CD WeekDesc 1 1 Week 01 2000 2 2 Week 02 2000 3 3 Week 03 2000 4 4 Week 04 2000 5 5 Week 05 2000 If I am running the select like this (this is the SQL which will be send out to the Database) SELECT "THE_WEEK_V"."WeekID" "WeekID" , "THE_WEEK_V"."WeekCD" "WeekCD" , "THE_WEEK_V"."WeekDesc" "WeekDesc" FROM "RD_VIEWS"."THE_WEEK_V" "THE_WEEK_V" The resultset is messed up again.... Week Week Id CD WeekDesc 1 1 Week 01 2000 53 53 Week 01 2001 2 2 Week 02 2000 54 54 Week 02 2001 3 3 Week 03 2000 55 55 Week 03 2001 4 4 Week 04 2000 The View is defined as Replace View RD_VIEWS.THE_WEEK_V As Locking Table RD.THE_WEEK For access SELECT * FROM RD THE_WEEK qualify row_number() over (order by WeekID) > 0 With check option; I have another Table for Month with the same columns for Month. On this table both SQL run in the same way......
That's exactly what I tried in the first place. Teradata is giving me an error with the message that a Sort is not allowed in a subquery.
No option, there are hundreds of small tables so the maintenance would be to intensive. Cheers Joerg
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