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Message Posted: Mon, 14 Aug 2006 @ 09:15:10 GMT


     
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Subj:   Re: Help needed with SQL problem
 
From:   ulrich arndt

You are writing "all of this would be in one column" but you example below shows three...

This (pseudo code - not tested) will create one column...

     select case when id = 1 then trim(col1) else trim(col2) end as col3
     from table a
          join
          (select calendar_date - current_date as id
           from sys_calendar.calendar
           where id between 1 and 2
          ) as r
          on 1=1
     ;

Ulrich



     
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