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Archives of the TeradataForumMessage Posted: Wed, 13 Sep 2006 @ 16:03:49 GMT
The answer to that depends on whether your source column is a character/date column and whether you are querying from Teradata utils or ODBC This one is sufficient for a Date source column from a teradata utility
SELECT DT1 (FORMAT 'YYYYMMDD') FROM JOE_001_D01.MY_DT001;
You will have to do this extra trick if you are querying from ODBC
SELECT CAST ( (DT1 (FORMAT 'YYYYMMDD')) AS CHAR(8) ) FROM
JOE_001_D01.MY_DT001;
Now if your source column was character format, then this is what you should do from a terdata utility
SELECT CAST(DT2 AS DATE FORMAT 'YYYY-MM-DD') (FORMAT 'YYYYMMDD')
FROM
JOE_001_D01.MY_DT001;
And this one is for ODBC
SELECT CAST( (CAST(DT2 AS DATE FORMAT 'YYYY-MM-DD') (FORMAT
'YYYYMMDD')) AS CHAR(8)) FROM JOE_001_D01.MY_DT001;
Regards Joseph Vinish D'silva
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