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Message Posted: Thu, 27 Apr 2006 @ 10:01:47 GMT

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The first part need not be true always.. It depends how PI(A,B) is calculated. The second part gives the actual formula for finding Hash which makes first part equal.

Assume PI(A,B) = contact(A,B) i.e. the two vales are converted to string and then appended then

     PI(A,B) <> PI(B,A) as PI(A,B) = AB and PI(B,A) = BA
     Since PI(A,B) = PI(A) + PI(B) + PI(A,B) which makes pI(A,B) = PI(B,A)

Regards,

Manish

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