|
|
Archives of the TeradataForum
Message Posted: Sun, 24 Jul 2005 @ 16:37:13 GMT
Subj: | | Re: Rank and dense_rank |
|
From: | | Dieter Noeth |
Dieter Noeth wrote:
> /* not implemented */
> sel
> department_number,
> dense_rank() over
> (partition by department_number order by salary_amount)
> last_name,
> salary_amount
> from employee;
>
>
> /* Replacement */
This time the right version:
sel
e.department_number,
dt.rnk,
e.last_name,
e.salary_amount
from cs_views.employee e
join
(
select
department_number,
salary_amount,
rank() over (
PARTITION BY department_number
ORDER BY salary_amount) as rnk
from cs_views.employee
group by 1,2
) dt
on e.salary_amount = dt.salary_amount
and e.department_number = dt.department_number
order by e.department_number, rnk
;
Dieter
| |