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Archives of the TeradataForum
Message Posted: Thu, 27 Feb 2003 @ 21:00:31 GMT
Subj: | | Re: Finding the last day of the month |
|
From: | | Dieter N�th |
Hayes, Jim M wrote:
| I have a need to find the last day of a month programatically (i.e. hardcoding Jan 31, etc. seems to me to be a kludge). | |
| I have the month/year and can append 01 to generate the first day of the next month thusly: | |
| ADD_MONTHS('2002-01-01',1)...... results in 2002-02-0 1. | |
| Now, I want to subtract 1 day from that date and come up with 2002-01-31. How do I do that? | |
ADD_MONTHS('2002-01-01',1) -1
or for any date:
select
add_months(calendar_date, 1)
- extract(day from add_months(calendar_date, 1));
Dieter
| |