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Message Posted: Thu, 17 May 2001 @ 21:20:14 GMT
I don't know if it will be as accurate enough for your needs, but instead of a circle, what if you worked with a triangle using the Pythagorean Theorem?
Distance = square root of ((lat2 - lat1)squared + (log2 - log1)squared)
I think SQL has exponents and square root that will allow this calculation.
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